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4000x^2-2410x-2930=0
a = 4000; b = -2410; c = -2930;
Δ = b2-4ac
Δ = -24102-4·4000·(-2930)
Δ = 52688100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52688100}=\sqrt{100*526881}=\sqrt{100}*\sqrt{526881}=10\sqrt{526881}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2410)-10\sqrt{526881}}{2*4000}=\frac{2410-10\sqrt{526881}}{8000} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2410)+10\sqrt{526881}}{2*4000}=\frac{2410+10\sqrt{526881}}{8000} $
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